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Mathematics, 28.06.2019 13:10 kingkushkaz2093
Mrs. culland is finding the center of a circle whose equation is x2 + y2 + 6x + 4y β 3 = 0 by completing the square. her work is shown. x2 + y2 + 6x + 4y β 3 = 0 x2 + 6x + y2 + 4y β 3 = 0 (x2 + 6x) + (y2 + 4y) = 3 (x2 + 6x + 9) + (y2 + 4y + 4) = 3 + 9 + 4 which completes the work correctly? (x β 3)2 + (y β 2)2 = 42, so the center is (3, 2). (x + 3)2 + (y + 2)2 = 42, so the center is (3, 2). (x β 3)2 + (y β 2)2 = 42, so the center is (β3, β2). (x + 3)2 + (y + 2)2 = 42, so the center is (β3, β2).
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Mrs. culland is finding the center of a circle whose equation is x2 + y2 + 6x + 4y β 3 = 0 by comple...
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