Using the following equation, find the center and radius of the circle. you must show all work and calculations to receive credit. x2 + 4x + y2 − 6y = −4

If c(x) = 4x – 2 and d(x) = x2 + 5x, what is (cxd)(x)

The position of a moving particle is given by the position function: f(t)=-9t-t^2-0.2t^3+0.1t^4 0 a. at what time does the particle reverse direction? b. when is the displacement positive? (round one decimal place and answer in interval notation) c. when is the displacement negative? (round one decimal place and answer in interval notation) d. when is the particle’s acceleration positive? (round one decimal place and answer in interval notation) e. when is the particle’s acceleration negative? (round one decimal place and answer in interval notation)

W-16=-12 solve each one step equation plz