If vx is the bisector of v, find the perimeter of vuw. a 35b. 46c. 58d. 70

D. 70

Step-by-step explanation:

If VX is the bisector of V, then UX=WX.

This implies that:

Group similar terms:

z=5

WU=2(z+6)

WU=2(5+6)

WU=2(11)=22 units

VW=VU=5z-1

Put z=5 to get;

VW=VU=5(5)-1

VW=VU=25-1

VW=VU=24

The perimeter of VWU=24+24+22=70 units

Perimeter of triangle VUW = 70.

Step-by-step explanation:

Since VX is angle bisector and VX is perpendicular to UW then triangle UVX is congruent to triangle WVX using ASA property.

then UV=WV...(i) {corresponding sides of congruent triangle are equal.}

and UX=WX ...(ii)  {corresponding sides of congruent triangle are equal.}

then 3z-4=z+6

3z-z=6+4

2z=10

z=5

then UW=(3z-4)+(z+6)=3(5)-4+(5)+6=22

WV=5z-1=5(5)-1=24

UV=WV=24

Then perimeter of triangle VUW is

UV+WV+UW=24+24+22=70

Hence final answer is:

Perimeter of triangle VUW = 70.

this is a very good question

step-by-step explanation:

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