Abag of marbles has 12 red, 7 yellow, 5 blue and 1 white. find the probability of selecting 4 marbles from the bag where all 4 are red.

There are 25 marbles: (12 red, 7 yellow, 5 blue, 1 white)

The probability of the first marble being red is 12/25 because there are 12 red marbles still available and no marbles are missing

The probability of the second marble being red is 11/24 because only 11 red marbles are available and 1 marble has already been selected from the pile

The probability of the third marble being red is 10/23 because only 10 red marbles are available and 2 marbles have already been selected from the pile

The probability of the fourth marble being red is 9/22 because only 9 red marbles are available and 3 marbles have already been selected from the pile

Since we are interested in all of these events occurring simultaneously, we must multiply the probability of all 4 events, like so:

Solving for this we are left with:

this shows a reflection over the x-axis and is translated one unit down and 6 units to the right (x + 6, y - 1)

hope this !

~just a girl in love with shawn mendes

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)