Write all possible digits to make the number 132* multiple of 2 and 3 but not 5.

  6

Step-by-step explanation:

In order for 132* to be a multiple of 2, the digit * must be even.

In order for 132* to be a multiple of 3, the sum of all digits must be a multiple of 3. That is (1 +3 +2 + *) = 6+* is a multiple of 3. Since 6 is already a multiple of 3, then * must be a multiple of 3.

Single-digit values of * that are both even and a multiple of 3 are 0 and 6. We know that any number ending in 0 will be a multiple of 5, so we cannot use that digit.

The only possible digit that makes 132* a multiple of 2 and 3, but not 5, is 6.

d) 30 units^2

area of rectangle = l × b

we know,

length = 10 unit

breadth = 3 unit

applying the formula,

= l × b

= 10 × 3

= 30 unit^2

happy to

pls mark as brainliest