In the model 1 n left parenthesis upper y subscript i right parenthesis equals beta 0 plus beta 1 upper x subscript i plus mu subscript i1nyi=β0+β1xi+μi, the elasticity of upper e left parenthesis upper y vertical line upper x right parenthesise(y x) with respect to x is:

the answer is 0.071

good luck! : d

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b