Practice 6.2: proving properties of parallelogramsuse slope to determine whether the given vertices form a parallelogram.1. a(-2,-1), b(-1,3), c (4,3), and d (3.-1)2. f(-1, 1), g (1.3), h (4,-2), and i (2, 4)use the distance formula to determine whether the given vertices form a parallelogram.3. | (0.0, k (1.5), l (4, 6), and m (3,0)4. mo.8), n(-1,2), o (5. 6), and p (6, 12)use the midpoint formula to determine whether the given vertices form a parallelogram.5. p(-2, 2), q (1.8), r (4,5), and s (3.-2)6.d (2, 2), e (4,5), f(10,6), and g (8,3) me if you could i'm trying to get my grade up

70,000 + 6,000 + 800 + 30

step-by-step explanation:

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step-by-step explanation:

i don't know

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.