G(x) = x + 1 and h(x) = x 2 - 4

h[g(x)] =

x 2 + 2x - 3
x - 1
x 2 - 3
x 2 - 1

2x-2

Step-by-step explanation:

h(gx)=h(x+1)

=2(x+1)-4

=2x-2

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

other answer is correct. i had used the radius of the radius somehow. a website: