What are the zeros of the function f(x)=x^3+x^2-6x

A

Step-by-step explanation:

Given

x³ +x ² - 6x ( to find the zeros equate to zero ), that is

x³ + x² - 6x = 0 ← factor out x from each term

x(x² + x - 6) = 0

To factorise the quadratic

Consider the factors of the constant term (- 6) which sum to give the coefficient of the x- term (+ 1)

The factors are + 3 and - 2, since

3 × - 2 = - 6 and 3 - 2 = + 1, hence

x(x + 3)(x - 2) = 0

Equate each factor to zero and solve for x

x = 0

x + 3 = 0 ⇒ x = - 3

x - 2 = 0 ⇒ x = 2

The zeros are x = - 3, x = 0, x = 2 → A

too hard the other guy did it

step-by-step explanation:

c

step-by-step explanation: