Can you find x for the following equation?
7x+12=3(5x-12)

x = 6

Step-by-step explanation:

Eliminate parentheses using the distributive property.

7x +12 = 15x -36

You have x-terms and constants on both sides of the equal sign. One way to approach this is to find the x-term with the least coefficient (it is 7x) and subtract everything on that side of the equation.

(7x +12) -(7x +12) = (15x -36) -(7x +12)

Simplify, also known as "collect terms."

0 = 8x -48

Now, divide by the coefficient of x: 8.

0 = x -6

Add the opposite of the constant: 6.

6 = x

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Alternate solution

By looking for the x-term with the smallest coefficient, we get a positive result when we subtract that term. If we were to subtract 15x from both sides of the equation, it would be ...

-8x +12 = -36 . . . . . . . with a negative x-coefficient

You can still work the problem this way, but it can introduce errors if you're not careful with signs. To finish this, we would subtract 12 to get the x-term by itself:

-8x = -48

Then we would divide by the x-coefficient, -8.

x = -48/-8 = 6 . . . . . same solution; same number of steps

Whenever you add, subtract, multiply, divide, you do the same thing to both sides of the equation.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

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mxb67

step-by-step explanation: