The work of a student to solve a set of equations is shown:
equation a: y = 4 − 2z
equation b: 4y = 2 − 4z
step 1:
−4(y) = −4(4 − 2z) [equation a is multiplied by −4.]
4y = 2 − 4z [equation b]
step 2:
−4y = 4 − 2z [equation a in step 1 is simplified.]
4y = 2 − 4z [equation b]
step 3:
0 = 6 − 6z [equations in step 2 are added.]
step 4:
6z = 6
step 5:
z = 1
in which step did the student first make an error?
step 1
step 3
step 4
step 2

If you would like to know in which step did the student first make an error, you can find this using the following steps:

y = 4 - 2z
4y = 2 - 4z

-4(y) = -4(4 - 2z)
4y = 2 - 4z

-4y = -16 + 8z ... Step 2
4y = 2 - 4z

0 = -16 + 8z + 2 - 4z

16 - 2 = 4z

14 = 4z

z = 14/4 = 7/2

The correct result would be: Student made an error in Step 2.

2/3x + 7 = 29

step-by-step explanation:

two thirds = 2/3

plus a number = x

at least 29 = 29

there for you should get 2/3x + 7 = 29

20%

step-by-step explanation: