Drag the tiles to the correct boxes to complete the pairs.
match each polynomial function with one of its factors.
f(x) = x3 − 3x2 − 13x + 15
f(x) = x4 + 3x3 − 8x2 + 5x − 25
f(x) = x3 − 2x2 − x + 2
f(x) = -x3 + 13x − 12
x − 2
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x + 3
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x + 4
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x + 5
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f(x) = x3 − 3x2 − 13x + 15    Factor:   x+3

f(x) = x4 + 3x3 − 8x2 + 5x − 25   Factor:  x+5

f(x) = x3 − 2x2 − x + 2     Factor:  x-2

f(x) = -x3 + 13x − 12  Factor:  x+4

Step-by-step explanation:

f(x) = x^3 − 3x^2 − 13x + 15

Solving:

We will use rational root theorem: -1 is the root of x^3 − 3x^2 − 13x + 15 so, factor out x+1

x^3 − 3x^2 − 13x + 15 / x+1 = x^2-2x-15

Factor: x^2-2x-15 =(x+3)(x-5)

So, factors are: (x+1)(x+3)(x-5)

Factor: (x+5)

f(x) = x^4 + 3x^3 − 8x^2 + 5x − 25

Solving:

We will use rational root theorem: -5 is the root of x^4 + 3x^3 − 8x^2 + 5x − 25, so factour out (x+5)

x^4 + 3x^3 − 8x^2 + 5x − 25 / x+5 = x^3-2x^2 +2x -5

So, factors are (x+5) (x^3-2x^2 +2x -5)

  Factor:  x+5

f(x) = x^3 − 2x^2 − x + 2    

Solving:

x^2(x-2)-1(x-2)

(x-2)(x^2-1)

(x-2) (x-1) (x+1)

Factor:  x-2

f(x) = -x^3 + 13x − 12

Solving:

-(x^3 + 13x -12)

We will use rational root theorem:

The 1 is a root of (x^3 + 13x -12) so, factor out x-1

Now solving (x^3 + 13x -12)/x-1 we get (x-3)(x+4)

So, roots are: - (x-1)(x-3)(x+4)

Factor (x+4)

Polynomial 1 = x + 3

Polynomial 2 = x + 5

Polynomial 3 = x - 2

Polynomial 4 = x + 4

Step-by-step explanation:

We are given with Polynomials and and some factors.

We have to match the correct Pair.

We Map the polynomials on the graph then check which factors matches.

Polynomial 1).

x³ - 3x² - 13x + 15

factors are ( x + 3 ) , ( x - 1 ) , ( x - 5 )

Polynomial 2).

factors are ( x + 5 )

Polynomial 3).

factors are ( x + 1 ) ,( x - 1 ) , ( x - 2 )

Polynomial 4).

factors are ( x + 4 ) ,( x - 1 ) , ( x - 3 )

Therefore,

Polynomial 1 = x + 3

Polynomial 2 = x + 5

Polynomial 3 = x - 2

Polynomial 4 = x + 4

, and

for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

note the following:

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for