Line jk passes through points j(–3, 11) and k(1, –3). what is the equation of line jk in standard form?

7x + 2y = –1
7x + 2y = 1
14x + 4y = –1
14x + 4y = 1

For this case we must find the slope of the JK line:

Substituting the JK points we have:

So, the equation is:

We find the cut point:

Then, finally the equation is:

Manipulating algebraically:

Option B

ANSWER

EXPLANATION

The given line JK passes through points J(–3, 11) and K(1, –3)

We obtain the slope using the formula;

.The equation is given by

40% off the regular price is the correct answer.

step-by-step explanation:

the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72