Awalking path is shaped like a rectangle with a width 7 times its length l. what is a simplified expression for the distance between opposite corners of the walking path?

The simplified expression is d = (5√2) L

Step-by-step explanation:

* Lets explain the problem

- A walking path is shaped like a rectangle

- The width of the rectangle is 7 times its length L

∵ The length of the rectangle is L

∵ The width is 7 times the length

∴ The width of the rectangle is 7L

- The distance between the opposite corners represented by the

  diagonal of the rectangle

- The length , the width and the diagonal formed a right triangle

- Its hypotenuse is the diagonal of the rectangle

- Its two legs are the length and the width of the rectangle

* Now we have right triangle use the Pythagoras Theorem to find

 the hypotenuse

∵ The length , the width and the diagonal of the rectangle are the

   sides of a right triangle

∵ The diagonal is the hypotenuse (h) of the triangle

∵ hypotenuse = √[L² + W²]

∵ The length = L and the width = 7L

∴ h = √[(L)² + (7L)²] = √[L² + 49L²] = √[50L²]

∵ √50 = 5√2

∵ √(L²) = L

∴ h = 5√2 L

∵ The diagonal of the rectangle is the distance between the

   opposite corners

∴ The distance between the opposite corners is (5√2) L

* The simplified expression is d = (5√2) L, where L is the length

  of the rectangle

p = 6s

step-by-step explanation: