The point-slope form of the equation of the line that passes through (-9, -2) and (1.3) is y-3=1/2(x-1). what is the slope-intercept form of the equation for this line?

y = 1/2x + 5/2

Step-by-step explanation:

y-3=1/2(x-1).

To get from point slope to slope intercept, distribute the slope

y-3 = 1/2 x -1/2

Then add 3 to each side

y-3+3 =1/2 x -1/2 +3

y = 1/2x +2 1/2

Or if we want the last term as an improper fraction

y = 1/2x + 5/2

need more information

step-by-step explanation:

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)