Ahot air balloon hovers above its launch site at an altitude of 100 meters. the pilot of the balloon sights a parking lot at a 12˚ angle of depression. to the nearest meter, what is the horizontal distance between the parking lot and the launch site?

The horizontal distance between the parking lot and the launch site is 470 meters

Step-by-step explanation:

Let

x>  the horizontal distance between the parking lot and the launch site

we know that

The tangent of angle of 12 degrees is equal to divide the altitude of 100 meters by the horizontal distance

so

tan(12°)=100/x

Solve for x

x=100/tan(12°)=470 meters

d. 145*2 is 290 than the total angle is 360 then minus 290 then divide by two

sina-sinb

cosb+cosa

tana-tanb

cos0+cos x pi/3

20tan

step-by-step explanation: