In a certain algebra 2 class of 29 students, 13 of them play basketball and 7 of them play baseball. there are 4 students who play both sports. what is the probability that a student chosen randomly from the class plays basketball or baseball?

16/29

Step-by-step explanation:

P(A∪B) = P(A) + P(B) - P(A∩B)

P(basketball or baseball) = P(basketball) + P(baseball) - P(both)

= (13/29) + (7/29) - (4/29)

= 16/29

The probability that a randomly chosen student plays either sport is 16/29.

step-by-step explanation:

hans did not square the 40-unit side; he merely multiplied it by 2.   incorrect.

answer: the resulting cross section is a rectangle. solution: a plane parallel to the base of a triangular prism will intersect a cross section that is the same shape as its bases. so the cross section is a triangle.

step-by-step explanation: