Solve the system of equations by substitution. 2x + y = 3z x + y = 6z what is the value for y from the first equation, that could be substituted into the second equation?

y = 3z - 2x

Step-by-step explanation:

Systems of equations can be solved by a number of know techniques, such as substitution, elimination or graphical approach.

We are required to solve the system of equations given via substitution;

2x + y = 3z

x + y = 6z

The question requires us to determine the value for y from the first equation, that could be substituted into the second equation.

We simply need to make y the subject of the formula from the first equation;

2x + y = 3z

To do this we subtract 2x on both sides of the equation;

2x + y -2x = 3z - 2x

y = 3z - 2x

This is the value of y from the first equation, that can be substituted into the second equation.

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.