Solve the equation for the interval

x=0,3π/2,π

Step-by-step explanation:

Given

sin^2  x+sin⁡x=0

sin x is a common factor

so,

sin⁡x (sin⁡x+1)=0

We can put both factors one by one equal to zero

sin⁡x=0

x=  sin^(-1)⁡0

sin⁡x  is zero at 0 and π

x=0,π

sin⁡x+1=0

sin⁡x= -1

x=  sin^(-1)⁡(-1)

sin is -1 for 3π/2

So,

x=3π/2

So,

x=0,3π/2,π

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