Elizabeth lives in san francisco and works in mountain view. in the morning, she has 3 transportation options (take a bus, a cab, or a train) to work, and in the evening she has the same 3 choices for her trip home.
if elizabeth randomly chooses her ride in the morning and in the evening, what is the probability that she'll use a cab exactly one time?

1/9 or 11%

Step-by-step explanation:

If she has 3 options for her way there, and 3 options on the way back, you do 3×3, which equals 9. If she only uses a cab once, it would be 1/9. If you need a percent, you do 1÷9, which equals 0.111111111. Then you multiply that by 100, which brings you to 11%.

4/9

Step-by-step explanation:

khan acadamy

5 x 14?

im new, sorry if this is wrong.

step-by-step explanation:

2x^2+5x+17

your welcome. : )