Afield with an area of 2880 ft2 has the shape of a rectangle, whose length is 12 ft larger than its width. find the dimensions of this field.

 The dimensions of the field are

width = 40 ft and length = 60 ft.  

Step-by-step explanation:  Given that a field with an area of 2880 ft² has the shape of a rectangle with length 12 ft larger than the width.

We are to find the dimensions of the field.

Let w ft be the width of the given rectangular field.

Then, the length of the field will be (w + 12) ft.

According to the given information, we have

Since the measure of a side of a rectangle cannot be negative, so w = 48.

This implies that

length of the field = w + 12 = 48 + 12 = 60 ft.

Thus, the dimensions of the field are

width = 40 ft and length = 60 ft.  

the revenue of the fitness center, y, is the product of two factors: the number of members and the fee paid by each member. there are 320 members now, but number of members goes down by 10 for each $5 increase in fees, so if x is the number of $5 price increases then members is equal to (320 - 10x). since the fee is currently $45, and the fee increases by $5 for every price bump x, the fee is given by (45 + 5x). so, revenue y is given by y = (320 - 10x)(45 + 5x).