Solve the equation for all real values of x.

a. pi/6
b. pi k, pi/6
c. pik
d. pi/6+pik

C

Step-by-step explanation:

1 / (cos x - sin x) = cos x + sin x

Multiply:

1 = (cos x + sin x) (cos x - sin x)

Distribute:

1 = cos² x - sin² x

Use trig identity:

sin² x + cos² x = cos² x - sin² x

2 sin² x = 0

sin x = 0

x = πk

Answer C.

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

i need a picture

step-by-step explanation: