Take all my points me
the high temperatures for dallas, texas in june 1985 and june 2013 are shown. use the data to create a comparative dot plot and comparative box plot and use them to compare the weather then and now. remember to use at least two module vocabulary words in your responses.

1. create a comparative dot plot for the data sets.

2. assess the degree of overlap between the data sets and compare the shapes, centers, and spreads of the two groups using the comparative dot plot.

3. create a comparative box plot for the data sets.

4. assess the degree of overlap between the data sets and compare the shapes, centers, and spreads of the two groups using the comparative box plot.

1. First two pictures below.

2.Both of them have large clusters that are a couple spaces away. The range is greater with June 2013.  

3. Second two pictures below. The third pic is June 1985 and fourth is June 2013.

4. The spread is smaller for June 1985. The boxes are seem to have the same proximity to each other which shows a tight center between the two box plots.

May be to late, but I'll post my answers to your questions anyway :)

geometry: triangles

solvers

lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584

hello,

b) 62.47% of the students are between 14 and 18 years old.

step-by-step explanation:

mean = 15 and standard deviation = 2

student between 14 to 18

formula used z-score

for age 14 , z score

using z-table , p(z> -0.5)=0.3085

for age 18 , z score

using z-table , p(z< 1.5)=0.9332

p(-0.5< z< 1.5)=0.9332-0.3085 = 0.6247

thus, 62.47% of the students are between 14 and 18 years old.

click to let others know, how is it

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step-by-step explanation: