What are the possible lengths and widths of a rectangle if its length is 8 centimeters longer than the width, and the area is less than or equal to 33 square centimeters?

Length = 11

Width = 3

Step-by-step explanation:

Conditions:

L = W + 8

A ≤ 33

We know both the L and W have to be less than or equal to 33, as the maximum area would be 33 * 1.

First, find the factors of 33.

1, 3, 11, 33.

Put them in pairs.

1,33

3,11

Find the pair with the difference of 8.

33 - 1 = 32

11 - 3 = 8

Assign them to the Length or Width and test them against the conditions.

L = 11

W = 3

11 = 3 + 8

3 * 11 = 33

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

8/k

step-by-step explanation: