Acircle is centered at the point (-3, 2) and passes through the point (1, 5). the radius of the circle is units. the point (-7, lies on this circle.

how would i do this?

Circle formula
(x-h)^2+(y-k)^2=r^2 where (h,k) is the center
and r=radius

to find the radius
we are given one of the points and the center
distnace from them is the radius
distance formula
D=
points (-3,2) and (1,5)
D=
D=
D=
D=
D=5

center is -3,2
r=5
input
(x-(-3))^2+(y-2)^2=5^2
(x+3)^2+(y-2)^2=25 is equation
radius =5
input -7 for x and solve for y
(-7+3)^2+(y-2)^2=25
(-4)^2+(y-2)^2=25
16+(y-2)^2=25
minus 16
(y-2)^2=9
sqqrt
y-2=+/-3
add 2
y=2+/-3
y=5 or -1

the point (-7,5) and (7,-1) lie on this circle

radius=5 units
the points (-7,5) and (-7,1) lie on this circle

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