How many multiples of 9 are there between 100 and 2,000?

hint: an = a1 + d (n − 1), where a1 is the first term and d is the common difference.

211

212

196

210

First Option

The number of multiples of 9 is 211

Step-by-step explanation:

Note that the first multiplo of 9 between 100 and 2000 is number 108. The last multiple of 9 is 1998.

If we use the arithmetic sequence to perform the calculation

So the first term is:

The last term is

The common difference is

Thus

We solve the equation for n and obtain the number of multiples of 9.

astronomers is your final answer! : )

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl