Mathematics, 27.09.2019 10:00 kb0767729

The equation of a circle is given below.
(x-20)^{2}+(y-0.05)^{2} = 81(x−20)
2
+(y−0.05)
2
=81left parenthesis, x, minus, 20, right parenthesis, start superscript, 2, end superscript, plus, left parenthesis, y, minus, 0, point, 05, right parenthesis, start superscript, 2, end superscript, equals, 81
what is its center?
((left parenthesis

,,comma
))right parenthesis
what is its radius?
if necessary, round your answer to two decimal places.

Answers: 1

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The equation of a circle is given below.
(x-20)^{2}+(y-0.05)^{2} = 81(x−20)
2
+(y...

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