How do i solve this?

a quadratic function is shown.

f(x) = 3x² + 30x + 27

what is the minimum value of this function? (hint: complete the square)

The minimum  happens at x = -b/2a

x = -30 / 2(3) = -30/6 = -5

Now replace x in the equation with -5 and solve:

3(-5)^2 + 30(-5) +27 = 75 - 150 + 27 = -48

The minimum is at (-5,-48)

256π units²   (answer b)

step-by-step explanation:

the formula for the surface area of a sphere of radius r

is             a = 4πr²

and so, if r = 8 units, then the surface area is:

a = 4π(8 units)² = 256π units²   (answer b)

answer: 48

just remember to use pemdas:

parentheses

expressions

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