At a pizza parlor you can have a choice of 3 toppings and 3 sizes. how many pizza combinations can be made if you choose one size and one topping?

The answer is 3.

Step-by-step explanation:

My reason of explanation is, lets say you want a Large pizza,

You get the large pizza and you put pepperoni on it. it's one pizza say

you want a small pizza with cheese on it. That's one size and one topping.

Say you want a medium size pizza with just sausage on it. that's one size, one topping.

You could make 9 different combinations.

Since you have 3 different sizes and three possible toppings, you'd simply multiply the first three variables by the second. Below, I've made a sample list for possible outcomes as an example.

Sizes                                          Toppings

Large                                         Pepperoni

Medium                                     Olives

Small                                         Green peppers

Possible Combinations

1. Large w/ Pepperoni

2. Large w/ Olives

3. Large w/ Peppers

4. Medium w/ Pepperoni

5. Medium w/ Olives

6. Medium w/ Peppers

7. Small w/ Pepperoni

8. Small w/ Olives

9. Small w/ Peppers

Hope this helps,

LaciaMelodii :)

3/5

step-by-step explanation:

double number line is not a standard concept, so it must have been defined in your textbook. assume top line is numerator.

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.