Two urns contain white balls and yellow balls. the first urn contains 10 white balls and 6 yellow balls and the second urn contains 8 white balls and 3 yellow balls. a ball is drawn at random from each urn. what is the probability that both balls are white?

5/11

Step-by-step explanation:

These are two independent events, because no matter which color the ball picked from jar #1 it will not affect the draw in jar #2.  

To evaluate the probability of both balls to be white, we first need to evaluate the probability of each draw resulting in a white ball then multiply those probabilities.

First urn: 10 white, 6 yellow balls

Chances to get a white ball: 10/16, or 5/8.

Second urn: 8 white, 3 yellow balls

Chances to get a white ball: 8 / 11

Chances for both balls to be white:

5/8 * 8/11 = 5/11

0.45 or 10/22

Step-by-step explanation:

Given

Total balls in urn 1=n(S_1 )=10+6=16

Total balls in urn 2=n(S_2 )=8+3=11

Let

P(W_1 )  be the probability that a white ball is chosen from urn 1

and

P(W_2 )  be the probability that a white ball is chosen from urn 2

So,

P(W_1 )=10/16

P(W_2 )=8/11

The probability that both are white:

P(W_1,W_2 )=P(W_1 )* P(W_2)

=10/16*8/11

=80/176  = 10/22

=0.45

The probability that both balls are white is 0.45 ..  

y=3x+4

step-by-step explanation:

given the points a(0,4) and b(-4, -8)

eqn of line ab: (y-4)/(x-0)=(-8-4)/(-4-0)

(y-4)/x=-12/-4=3

y=3x+4

1.30

step-by-step explanation: