Acar leave p and drives 3km north to q. from q it's drives 15km on a bearing north 45degree east to r. find the distance and bearing of r from p

17.25 km N37.9°E

Step-by-step explanation:

The way to solve this is to determine the vertical and horizontal distances traveled.

The bearing means 45° east of north.

Vertically, the car travels a distance of:

y = 3 + 15 cos 45°

y = 3 + 7.5√2

y ≈ 13.6

Horizontally, the car travels a distance of:

x = 15 sin 45°

x = 7.5√2

x ≈ 10.6

The total distance we find with Pythagorean theorem:

d = √(x² + y²)

d = √(10.6² + 13.6²)

d ≈ 17.25

The bearing from north we find with tangent:

tan θ = x / y

tan θ = 10.6 / 13.6

θ ≈ 37.9°

127

whether it's diameter, or radius, i believe if i remember correctly from school, every amount has to always add up to 180. so if you take 53, and starting adding, long story short, taking 127 and adding it to 53, gives you 180.