A4-digit number ends in 3. if you put the number 3 in the first position, the number will decrease by 738. find the original 4-digit number.

4153. Read the explanation please. There is no point in just reading the answer because the same type of problem can come up in the RSM homework or in a test and you will have no idea how to solve it.

Step-by-step explanation:

Form an equation with the information you know.

1. Moving the last digit, 3, to the first position is the same as doing (x-3)/10 +3000, where x is the original 4-digit number.

    Why it works: This expression works because first, you subtract 3 from the original number. This removes 3 from the last digit, but leaves a zero there. To remove the zero, you divide by 10. Finally, to put the 3 at the first position, you add 3000.

2. Since you know that the number will decrease by 738, you can do the second part of forming the equation. Make the expression equal to x - 738, like so --> (x-3)/10 + 3000 = x - 738

Solve the equation.

3. (x-3)/10 + 3000 = x-73

   (x-3)/10 = x - 3738

   x-3 = 10x - 37380

   x = 10x - 37377

   -9x = -37377

   x = 4153

Well, I've got to get back to my RSM homework. I hope this helped!

P.S.- The next time you have a question, email your RSM teacher (I'm assuming you go to RSM) because he/she is much more qualified then me (I'm only 12) and you don't really know if you can trust people giving you answers on

u rich

step-by-step explanation:

1260=3*6*7*10=3^2*2^2*7*5 perfect cude = 3^3*2^

step-by-step explanation: