Bc is tangent to circle a at point b. what is m2acb if mzcab = 22° ?

68°

Step-by-step explanation:

We know that sum of 3 angles in a triangle is 180°.

In  ΔBAC, there are angles B, A, and C. Thus we can say:

B + A + C = 180

Since, BC is tangent to circle, the point of tangency, B is a 90 degree angle. So angle B is 90.

Also, given angle CAB is 22, which, in other word, is angle A is 22.

Thus, we can write:

B + A + C = 180

90 + 22 + C = 180

112 + C = 180

C = 180 - 112 = 68

Measure of angle ACB = 68°

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation:

c.

step-by-step explanation:

substitution for (0,1)

y=x^2+4x+1

1=0^2+4(x)0+1

1=0+4(x)0+1

1=4(x)0+1

1=0+1

1=1

substitution for (-3,-2)

y=x+1

-2=-3+1

-2=-2