One brand of vinegar has a ph of 4.5. another brand has a ph of 5.0. the equation for the ph of a substance is ph = –log[h+], where h+ is the concentration of hydrogen ions. what is the approximate difference in the concentration of hydrogen ions between the two brands of vinegar?

2.16 * (10^-5).

Step-by-step explanation:

5 = -log H+

5 = log (1 / H+)

1/ H+ = 10^5

H+ = 10^-5

In a similar fashion  the other brand has H+ of 10^-4.5.

So the difference in hydrogen ion concentration =  10^(-4.5) - 10^(-5)

= 2.16 * (10^-5).

The vinegar with pH 4.5 has 2.2*10^-5 more hydrogen ions than the vinegar with pH 5.0.

Explanation:

To identify the difference, we must first find the H+ of both. We can do this by using the equation [H+]=10^-pH. After we do that we know that the vinegar with a pH of 5.0 has [H+]=1.0*10^-5 and the vinegar with a pH of 4.5 has [H+]=3.2*10^-5. The difference is found by subtraction.

(3.2*10^-5)-(1.0*10^-5)=2.2*10^-5

step-by-step explanation:

if x = 2 you have to find x to finish the problem

55/i dont know i do it for the points

step-by-step explanation: