If x+y = 6, y+z = 7, and z+x = 9, what is the average (arithmetic mean) of x, y, and z?

11/3 . . . or . . . 3 2/3

Step-by-step explanation:

Adding the three equations will give 2x+2y+2z:

(x +y) +(y +z) +(z +x) = 6 +7 +9

2x +2y +2z = 22

Dividing by 2 gives the sum of three variables:

x +y +z = 11

The average of x, y, and z is their sum divided by 3:

(x +y +z)/3 = 11/3

y = 3x+4

step-by-step explanation:

to find the slope

slope = (y2-y1)/ (x2-x1)

    = (-8-4)/ (-4-0)

    = -12/-4

  = 3

using the slope intercept form of a line

y= mx+b

we know the slope is 3

we know the y intercept is 4 ( the point where it crosses the y axis or x=0)

y = 3x+4