Adog and a cat are 200 meters apart when they see each other. the dog can run at a speed of 30 m/sec, while the cat can run at a speed of 24 m/sec. how soon will the dog catch the cat if the dog starts running after the cat?

The dog will catch the cat at time greater than 33.33 sec

Step-by-step explanation:

Let

x> distance the cat runs before being caught by the dog, if they started running towards each other simultaneously

Remember that

The speed is equal to divide the distance by the time

v=d/t

solve for t

t=d/v

so

equate the time

x/24=(200+x)/30

30x=24(200+x)

30x=4,800+24x

30x-24x=4,800

x=4,800/6=800 m

t=d/v=800/24=33.33 sec

or

t=(800+200)/30=1,000/30=33.33 sec

Remember that

the dog starts running after the cat

therefore

The dog will catch the cat at time greater than 33.33 sec

step-by-step explanation:

5×5×5+2(8)÷2(2)+3(3)

15+16÷4+9

31÷13

do 31÷13 and u will get ur answer

gmt is 4 hrs ahead of edt so just add four hours to 1: 14: 20 (minutes and seconds stay the same)

gmt is 5: 14: 20

hope this !

~just a girl in love with shawn mendes