How do you find an area of a triangle with a height of 2.75 and a base of 1 and 3/4?

A = 2  13/32

Step-by-step explanation:

The formula for the area of a triangle of base b and height h is

A = (1/2)(base)(height) = (1/2) · b · h

Here, the area is:

A = 2  13/32

A = (1/2)(1  3/4)(2.75)

Rewrite 1  3/4 as the improper fraction 7/4, and 2.75 as the improper fraction 11/4.

Then:

A = (1/2)(7/4)(11/4), which comes out to A = 77/32, or 2  13/32.

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!

i would say b) is your answer

sorry if im wrong

step-by-step explanation: