Correct answer only !

the lengths of trout in a lake are normally distributed with a mean of 30 inches and a standard deviation of 4.5 inches.

enter the z-score of a trout with a length of 28.2 inches.

z = -0.4.

Step-by-step explanation:

Here's the formula for finding the z-score (a.k.a. standardized normal variable) of one measurement of a normal random variable :

,

where

Let the length of a trout in this lake be inches.

.

For this measurement, . Apply the formula to get the z-score:

.

the answer is c

hope this !

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b