Solve the equation z^2 + 3z - 18 = 0

This is a quadratic equation. You have to factor it.

You have to find two numbers that meet the following requirement:

-When multiplied, is equal to -18.

-When added, is equal to 3.

The two numbers are 6 and -3.

Now factor it:

(x + 6)(x - 3)

So x = -6 or x = 3

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3