How do you prove 4 (cos^4a + sin^4a) / (3+cos4a) = (cos^4a-sin^4a) sec2a?

Step-by-step explanation:

Step 1: (sin²A+cos²A)²

Step 2: (a+b)² = a²+b²+2ab

Step 3: (sin²A+cos²A)²=sin⁴+cos⁴+2sin²Acos²A

make sure to use: sin²a+cos²a=1

Step 4: (1)²-2sin²Acos²A = sin⁴A+cos⁴A

Step 5: 1-2sin²Acos²A = sin⁴A+cos⁴A

step-by-step explanation: h: (- 3, 6)

m: (1, - 2)

o: (7, 6)

r: (- 9, - 2)

midpoint of hm: (- 1, 2)

midpoint of or: (- 1, 2)

therefore, b is the midpoint of both diagonals bisect each other !

to prove the diagonals are perpendicular, show that the product of the slopes = - 1

yes the data was not prsented

step-by-step explanation: