Write the point-slope form of the line that passes through (6, 1) and is perpendicular to a line with a slope of -3. include all of your work in your final answer. type your answer in the box provided or use the upload option to submit your solution

ANSWER

EXPLANATION

We want to write the point-slope form of the line that passes through (6, 1) and is perpendicular to a line with a slope of -3.

The slope of this line is negative reciprocal of -3.

The point-slope form is given by:

We substitute the point and the slope to get;

y - 1 = 1/3*(x - 6)

Step-by-step explanation:

point-slope form of a line:

y - y1 = m*(x - x1)

where x1 and y1 are the coordinates of the point included in the line and m is its slope.

Two lines are perpendicular when the multiplication of their slopes is equal to -1. In this case,

m*(-3) = -1  

m = 1/3

Replacing this slope and the coordinates of point (6, 1) we get:

y - 1 = 1/3*(x - 6)

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step-by-step explanation: