Iai − ibi + ici , if a=−8; b=−5; c=1

plze

4

Step-by-step explanation:

to solve | a | - | b | + | c | we need to plug in the given values

a = -8

b = -5

c = 1

the | | bars mean absolute value which is the exact value a number is away from 0 on a number line. an absolute value has to be positive, not a negative, as you cant be negative spaces away from something. plugging in the values into the equation we have:

| -8 | - | -5 | + | 1 |

the absolute value of -8 is 8, as -8 is 8 units away from 0 on a number line

like wise with -5, the absolute value of -5 is 5, as -5 is 5 units away from 0 on a number line

1 is the absolute value of 1 as its 1 unit away from 0 on a number line

the new expression looks like the following:

8 - 5 + 1

now we just add/subtract

8 -5 = 3

3 + 1 = 4

the solution to this expression is 4

5/6

step-by-step explanation:

if i remember correctly with perpendicular stuff you just take away the negative

fsfd

step-by-step explanation:

fdddff