Write a polynomial that represents the area of a rectangle with side lengths of 7x-2 and 3x-5

21x^2 - 41x + 10

Step-by-step explanation:

The area of a rectange is length x width.

L = 7x-2

W = 3x-5

So, you would do (7x-2)x(3x-5).

To do this, you can do FOIL.

F (first times first) - (7x)(3x)=21x^2

O (outside times outside) - (7x)(-5)= -35x

I (inside times inside) - (-2)(3x)= -6x

L (last times last) - (-2)(-5) = 10

So, it is 21x^2 - 35x - 6x +10

Then you combine like terms giving you:

21x^2 - 41x + 10

21x^2 - 41x + 10

Step-by-step explanation: If the lengths are even then the number would be angle.

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