Consider a right cone with radius 2 and height 6. its volume is v = π(2)26, or 8π units3.

if the height is changed to 3, does this have the same effect on the volume as changing the radius to 1?

if the height is now 3, then the new volume is π units3.

if the radius is now 1, then the new volume is π units3.

therefore, changing the height to half of its original value and changing the radius to half of its original value does the volume. halving the height of the cone the volume, while halving the radius of the cone results in the volume.

4, 2, not have the same effect on, halves, 1/4

Step-by-step explanation:

The correct answers are:

A. 4

A. 2

A. Not have the same effect on.

C. Halves

B. 1/4

If the height is now 3, then the new volume is 4 units. If the radius is now 1, then the new volume is 2 units. Therefore, changing the height to half of its original value and changing the radius to half of its original value does not have the same effect on the volume. Halving the height of the cone halves the volume, while halving the radius of the cone results in 1/4 the volume.

  about 5.6 days

step-by-step explanation:

we can fill the given information into the decay equation and solve for the value of t at which half the sample remains.

the half-life is about 5.6 days.

oof cheaters cheat because they’re lazy that’s why i cheat xd

: )

step-by-step explanation: