Find the probability. two 6-sided dice are rolled. what is the probability that the sum of the two numbers on the dice will be greater than 10?

3/36 (1/12) or 0.08333... or approximately an 8% chance of rolling a sum greater than 10 (i.e., sum of 11 or 12)

Step-by-step explanation:

There are 36 unique combinations of the 6 sides of the 2 dice

Roll a 1 and a 1 = one combination

Roll a 6 and a 6 = another combination

But roll a 2 and a 3 is treated as unique and different from rolling a 3 and a 2

If you create a 6 x 6 grid where you map out all the possible unique sum combinations of rolling two 6-sided dice you'll find at the very end/bottom of the grid that there are two ways to roll an 11 (5 then a 6; 6 then a 5) and only one way to roll a 12 (6 then a 6). That means there are 3 ways to get a sum greater than 10 out of 36 unique possible combinations

Can you guess why the sum of 7 is "Lucky Seven"?

the final price would be 29.6925

step-by-step explanation:

39.59 minus 25% equals 29.6925

percentage - 25%

probability - 0.25

we know,

total amount of students in class = 20

total boys = 10

total girls = 10

no of girls who wear glasses = 10/2 = 5

probability of choosing a girl with glasses is =

number of girls wearing glasses/total number of students in the class = 5/20

thus, percentage of selecting a girl wearing glasses will be

= 5/20 × 100

= 5 × 5

25%

therefore,

probability will be 0.25

happy to

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