Use substitution to solve the system of equations. 2x+4y=8 3x-5y=1

ANSWER

The solution is (2,1)

EXPLANATION

The given equations are:

2x+4y=8...(1)

3x-5y=1...(2)

We make x the subject in the first equation to get:

2x=8-4y

This means that,

x=4-2y...(3)

Put equation (3) into equation (2)

3(4-2y)-5y=1

Expand:

12-6y-5y=1

-6y-5y=1-12

-11y=-11

y=1

Put y=1 into equation (3).

x=4-2(1)=2

The solution is (2,1)

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

answer:   (s+1)(s+4)

step-by-step explanation:

factor s2+5s+4

s2+5s+4

=(s+1)(s+4)