If a = 11 ft, b = 5 ft, and c = 7 ft, what is the surface area of the geometric shape formed by this net?
a. 167 sq. ft.
b. 145 sq. ft.
c. 117.5 sq. ft.
d. 147 sq. ft.

the answer is B.  145 sq. ft.

Step-by-step explanation:

find the area of the first 2 triangles

A = 1/2 bh

A = 1/2 ba

a = 1/2 (11 ft.) (5 ft)

a =  27.5 sq ft.

A = 1/2 cb

a = 1/2 (5 ft) (7 ft)

a = 17.5 sq. ft

find the area of the rectangle

A = lw

a = (11 ft.)(5 ft.)

a = 55 sq. ft

Then add all together

2(27.5 sq.ft) + 2(17.5 sq. ft) + 55 sq.ft. = 145 sq. ft.

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

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step-by-step explanation: