The length of a rectangle is 3 more days than than twice its width. the perimeter of the rectangle is 42 centimeters. what is the length of the rectangle

Solution:

It is given that length of a rectangle is 3 more days than than twice its width. The perimeter of the rectangle is 42 centimeters.

So,

Let Required Breadth of Rectangle be x

Now, We have ;

Perimeter of Rectangle = 2(l+b)

Perimeter of Rectangle = 2(2x+3+x)

42 = 2(3x+3)

42 = 6x + 6

42 - 6= 6x

36= 6x

x = 6 cm

Length of Rectangle = 2(6) + 10

Length of Rectangle = 22 cm

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

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