The two lines y=2x+8 and y=2x-12 intersect at x-axis at p nad q. work out the distance pq

ANSWER

|PQ|=10

EXPLANATION

The first line is

y=2x+8

We put y=0 to find the x-intercept.

0=2x+8

-2x=8

x=-4

(-4,0) are the coordinates of P.

The second equation is

y=2x-12

To find the x-intercept, we put x=0 into the formula:

0=2x-12

-2x=-12

x=6

The coordinates of Q are (0,6).

The distance between these two points.

|PQ|=|6--4|=10