Abasketball player who shoots 80% from the free throw line attempts 2 free throws. let event a be a made first attempt and event b be a made second attempt.

which statement about the conditional probability is true?

1 the conditional probability of event b given event a is p(b|a)=p(b) when two events are not independent.

2 the conditional probability of event b given event a is p(b|a)=p(b)p(a) when two events are independent.

3 the conditional probability of event b given event a is p(b|a)=p(a)p(b) when two events are independent.

4 the conditional probability of event b given event a is p(b|a)=p(a and b)p(a) when two events are not independent.

Answer with explanation:

Probability of getting shoot from free throw line= 80% =0.80

Probability of not getting shoot from free throw line = 100% - 80% = 20% = 0.20

A student attempt throwing ,twice from free throw line.

A= First Attempt

B= Second Attempt

→If Events , A and B are Independent,then Probability of A and B is given as

P (A ∩ B)= P(A) × P(B)

→And,Conditional probability of event A has definitely occurred  and then probability that event B will occur,when these two events A and B are not Independent, is given by:

Option 4:  The conditional probability of Event B given Event A is P(B|A)=P(A and B)/P(A) when two events are not independent.

table a is wierd

step-by-step explanation:

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